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imnotsmart
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A "seconds" pendulum is one that goes through its equilibrium position once each second. (The period of the pendulum is 2.000 s.) The length of a seconds pendulum is 0.9927 m at Tokyo and 0.9942 m at Cambridge, England. What is the ratio of the free-fall accelerations at these two locations?
Cambridge / Tokyo) = 1 +?
How do I work this problem? Any help would be appreciated.
Cambridge / Tokyo) = 1 +?
How do I work this problem? Any help would be appreciated.