A "seconds" pendulum is one that goes through its equilibrium position once each second. (The period of the pendulum is 2.000 s.) The length of a seconds pendulum is 0.9927 m at Tokyo and 0.9942 m at Cambridge, England. What is the ratio of the free-fall accelerations at these two locations?(adsbygoogle = window.adsbygoogle || []).push({});

Cambridge / Tokyo) = 1 +?

How do I work this problem? Any help would be appreciated.

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# Homework Help: Simple Harmonic Motion and free-fall accelerations

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