A simple pendulum suspended in a rocket ship has a period T0. Assume that the rocket ship is near the earth in a uniform gravitational field. (If A and E are true, and the others are not, enter TFFFT).(adsbygoogle = window.adsbygoogle || []).push({});

A) If the ship accelerates upward, the period decreases.

B) If the ship goes into freefall, accelerating downward at 9.81 m/s2, the pendulum will no longer oscillate.

C) If the ship moves upward with a constant velocity, the period decreases.

D) If the mass of the pendulum doubles, the period increases.

E) If the length of the pendulum is doubled, the new period will be the square root of two times T0.

I thought I had the answer on this one. But I didn't..

My instinct was

A)F

B)F

C)T

D)F

E)T

I also tried, TTTFT, TFTFT and FTTFT (ABCDE)

As you can see I was very confident that C=T D=F E=T.. And I was wrong.

Anyone have a better idea?

**Physics Forums - The Fusion of Science and Community**

# Simple harmonic motion in a rocket?

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

Have something to add?

- Similar discussions for: Simple harmonic motion in a rocket?

Loading...

**Physics Forums - The Fusion of Science and Community**