- #1

- 40

- 0

it oscillates between 2 points 5cm apart and completes 40 oscillations in 1min

whats its max speed?

Please help i always get the wrong answer

The answer is 0.44 but why?

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter koat
- Start date

- #1

- 40

- 0

it oscillates between 2 points 5cm apart and completes 40 oscillations in 1min

whats its max speed?

Please help i always get the wrong answer

The answer is 0.44 but why?

- #2

gneill

Mentor

- 20,925

- 2,866

it oscillates between 2 points 5cm apart and completes 40 oscillations in 1min

whats its max speed?

Please help i always get the wrong answer

The answer is 0.44 but why?

Show your solution attempt. We can't tell what's going wrong if we don't see what you're doing.

- #3

- 40

- 0

2pi*40/60= 4/3 pi

f= 4/3pi*1/2= 2/3

vmax= 2pi*2/3*2.5*10^-2

but the answer is wrong :(

f= 4/3pi*1/2= 2/3

vmax= 2pi*2/3*2.5*10^-2

but the answer is wrong :(

- #4

gneill

Mentor

- 20,925

- 2,866

2pi*40/60= 4/3 pi

f= 4/3pi*1/2= 2/3

vmax= 2pi*2/3*2.5*10^-2

but the answer is wrong :(

Actually, your answer is correct. Looks like the answer key is wrong

You've correctly calculated the frequency of the oscillations:

## A = 5 cm/2 ##

## f = 40 cycles/min ##

##\omega = \frac{40 cycles}{min} \times \frac{1\;min}{60\;sec} \times \frac{2 \pi \; rad}{cycle} = \frac{4}{3}\pi \frac{rad}{sec}##

## v = A \omega = \frac{10 \pi}{3}\frac{cm}{sec} = 0.105 m/s ##

Share: