(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

An object undergoing SHM with a period 0.9s and amplitude of 0.32 m at t=0 the object is at 0.32 m and is instantaneously at rest. Calculate the time it takes the object to go a) from 0.32 to 0.16 m

b) from 0.16 m to 0

i can do a but dont understand why when i do the calculation x is not -1/2 and is 1/2

2. Relevant equations

x=Asin(wt)

3. The attempt at a solution

so for first part 1/2 = 0.32 cos (2+2/9)*pi * t

i get 0.15 correct answer and for part b i do the same thing because it is the same distance excpt i shift the graph so t1 is at 0.16 like this 0.16 = a cos ((wt) - pi/4)

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# Simple harmonic motion question please help!

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