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Simple harmonic motion solved for time
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[QUOTE="MaxBicknell, post: 5475577, member: 594295"] [h2]Homework Statement [/h2] A particle of mass 0.50 kg performs simple harmonic motion along the x-axis with amplitude 0.55m and period 4.3 seconds. The initial displacement of the particle is -0.30 m and it is traveling in the positive x-direction. The phase constant of the motion (Φ) = -2.15 rad. Find the time at which the particle first reaches x = +0.3m. Relevant equations: [h2]Homework Equations[/h2] x(t) = Acos(ωt + Φ) f = 1/T = 0.2326 Hz ω = 2πf = 1.4612 rad/s [h2]The Attempt at a Solution[/h2] Rearrange for t: t = [arccos(x/A) - Φ]/ω t = [arccos(0.6/0.55) + 2.15]/1.4612 This is giving me a maths error because arccos(x > 1) does't exist, but 0.6m is the total displacement. Even when I use 0.3 as my measurement for x I get a ridiculous value for t: t = [arccos(0.3/0.55) + 2.15]/1.4612 t = 40.4423 s Not sure where I'm going wrong. Any help would be great! [/QUOTE]
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Simple harmonic motion solved for time
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