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Simple Harmonic Motion Tuning Fork Question

  1. Apr 21, 2005 #1
    A tuning fork vibrates at a frequency of 264 Hz and the tip of each prong moves 1.66 mm to either side of center. Calculate the maximum speed of the tip of a prong.

    So far I've found that Vmax = omega*A, but I don't know how to find A. Am I going in the wrong direction? Or is there a way to find A that I don't know about yet..?
  2. jcsd
  3. Apr 21, 2005 #2

    Doc Al

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    Staff: Mentor

    That's the amplitude.
  4. Apr 21, 2005 #3
    Oh haha, I knew it must've been something stupid, thanks.
  5. Apr 21, 2005 #4
    Ok so I figured that Vmax would be omega*A, but it isn't correct. I know that
    v=-omega*A*sin(omega*t) (yeah I need to learn how to write equations better)

    so I assumed that in the problem, it's basically an initial value, so t=0. So that would leave v=omega*A.

    From this I got Vmax = (2pi/T)(A)
    and T=1/f

    so Vmax = (2pi/(1/f))(A)

    I guess this is incorrect. Oh and I didnt forget to convert mm to m. Any pointers?
  6. Apr 21, 2005 #5
    woops nevermind... I must have entered it in my calculator wrong haha sorry. Thanks for the help Al.
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