1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Simple Harmonic Motion: Two Springs One Mass

  1. Oct 7, 2012 #1
    1. The problem statement, all variables and given/known data

    Two springs each have spring constant k and equilibrium length (L). They are both stretched a distance (L) and attached to a mass m and two walls.

    At a given instant, the right spring constant is somehow magically changed to 3k (the relaxed length remains L). what is the resulting x(t)?

    Take the initial Position to be x=0

    2. Relevant equations



    3. The attempt at a solution

    My problem is figuring out the Force equations of the system.

    Could it be:
    F(spring system) = -kx-3kx
    where the 2L lengths on each side of the mass doesn't matter

    or
    F(spring system) = -k(2L+x)-3k(2L-x)
    where the 2L lengths on each side of the mass does matter

    or

    Something else that I'm not considering.

    I'm confused because the textbook doesn't have example problems on a similar system of two springs one mass. Also, my second guess would make a really complicated differential equation, where I don't think I could use use a guess such x(t)=Ae^(alpha*t) because there is a constant in the equation.

    Can someone explain to me the correct equation for the spring force?
     
  2. jcsd
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Can you offer guidance or do you also need help?
Draft saved Draft deleted



Similar Discussions: Simple Harmonic Motion: Two Springs One Mass
Loading...