1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Simple Harmonic Motion

  1. Mar 27, 2006 #1
    "A 0.25kg mass on a vertical spring oscillates with a frequency of 1.0 Hz. Suppose a 0.50kg mass were instead suspended from the same spring. What would be the frequency of oscillation in this case?"

    This is what I did:
    [tex]\frac{f_{1}}{f_{2}} = \frac {\sqrt{\frac{k}{m_{1}}}}{\sqrt{\frac{k}{m_{2}}}}[/tex]
    [tex]\frac{f_{1}}{f_{2}} = \sqrt{\frac{m_{2}}{m_{1}}}[/tex]
    [tex]f_{2} = \frac{1}{4} f_{1}[/tex]
    [tex]f_{2} = 0.25 Hz[/tex]
    however, the answer is 0.71 Hz. What did I do wrong?
     
  2. jcsd
  3. Mar 27, 2006 #2

    Tom Mattson

    User Avatar
    Staff Emeritus
    Science Advisor
    Gold Member

    You got the ratio [itex]m_2/m_1[/itex] wrong. The ratio is 2, which means that [itex]\sqrt{m_2/m_1}=\sqrt{2}[/itex], but you have 4.

    So in short I think you squared the 2 when you should have taken the square root.
     
  4. Mar 27, 2006 #3
    You are absolutely correct! I didn't realize I did that. Thanks for the prompt reply!
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Simple Harmonic Motion
Loading...