Solving Simple Harmonic Motion Problems: A Guide| Physics HW

In summary, the conversation discusses a physics problem involving a bullet colliding with a block attached to a spring. The goal is to find the velocity of the bullet after the collision. The conversation mentions using the equations E = K + U and conservation of linear momentum to solve the problem. It is also noted that the collision is perfectly inelastic and the spring has no effect on the velocity immediately after the collision. The conversation concludes with the problem being solved.
  • #1
suspenc3
402
0

Homework Statement



http://www.physics.umd.edu/courses/Phys122/Noyes/HW/hw1.pdf (pg 3)

Homework Equations



Im guessing that E = K + U has something to do with it


The Attempt at a Solution



Not really sure where to start..I tried a few approaches but none of them got me anywheres E = 1/2mv^2 + 1/2 kx^2..but I am missing too many things..

Any help?
 
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  • #2
when the bullet colides, it sticks. This means that energy is not conserved but something else is.
 
  • #3
by the way, the fact that the clay sticks and that the collision is therefore perfectly inelastic is one of those "assumptions"
 
Last edited:
  • #4
conservation of linear momentum?
 
  • #5
yes. now you can use that in combination with energy.
 
  • #6
so I have [tex]\frac{mv +Mv_2}{m+M} = v_f[/tex] where [tex]Mv_2[/tex] is going to be 0 since it is at rest?

and [tex]E=1/2mv^2 + 1/2kx^2[/tex]

Do i let m = m+M? and will 1/2kx^2 be 0 since the block can be considered to be at point x=0?...set it to zero and solve for v?
 
  • #7
you actually don't need to use energy until you are ready to find the amplitude. You already have enough information to find the velocity.
 
  • #8
So imediately after the collision, the spring has no effect on the velocity?
 
  • #9
that's correct. two ways to understand that
1) imediately after colision, spring is not compressed and therefore applies no force.

2) even if it were compressed, a force causes an acceleration which only changes velocity of some period of time.
 
  • #10
Solved it..Thanks for the help
 
  • #11
good job, np
 

1. What is Simple Harmonic Motion?

Simple Harmonic Motion (SHM) is a type of periodic motion in which a body oscillates back and forth around an equilibrium position. It is characterized by a restoring force that is directly proportional to the displacement of the object from its equilibrium point.

2. What are the factors that affect Simple Harmonic Motion?

The factors that affect Simple Harmonic Motion include the mass of the object, the spring constant of the restoring force, and the amplitude and frequency of the oscillations.

3. How is Simple Harmonic Motion related to Hooke's Law?

Hooke's Law states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position. This is the same principle that governs Simple Harmonic Motion, as the restoring force in SHM is also directly proportional to the displacement of the object from its equilibrium point.

4. What are some real-life examples of Simple Harmonic Motion?

Examples of Simple Harmonic Motion can be found in many everyday objects and phenomena, such as a pendulum swinging, a mass on a spring bouncing up and down, or the vibrations of a guitar string.

5. How is Simple Harmonic Motion different from other types of motion?

Simple Harmonic Motion is different from other types of motion in that it is a periodic motion characterized by a restoring force that is directly proportional to the displacement of the object. This is in contrast to other types of motion, such as uniform circular motion, which do not have a restoring force and therefore do not exhibit oscillatory behavior.

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