A mass of 0.100 kg is supported in equilibrium by two identical springs of negligible mass having spring constants k= 0.050 N/m. In the equilibrium position, the springs make an angle of 30 degree with the horizontal and are 0.100 m in length. If the mass, m, is pulled down a distance of 0.020 m and released, find the period of the resulting oscillation.(adsbygoogle = window.adsbygoogle || []).push({});

MY ATTEMPT:

angular frequency= square root (2k/m)

frequence= (1/2pi)angular frequency

Period= 1/frequency

It seems to be too easy like that so am not sure am right...:uhh:

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# Homework Help: Simple harmonic motion

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