A 50 g block is hung from a vertical spring. The spring constant is 4 N/m. We let go of the block when the spring is not stretched.What is the maximal stretch of the spring?
Fs=k times x
The Attempt at a Solution
At the maximal stretch, the block is at equilibrium since it stops falling down. Gravity force is then equal to the spring force.
we have: Fs=mg
kx = mg
so x = mg/k = 0.05*9.8 / 4 = 0.1225 meters
This answer is wrong.
Can anyone help me? My reasoning looks logic to me :(