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## Homework Statement

A 50 g block is hung from a vertical spring. The spring constant is 4 N/m. We let go of the block when the spring is not stretched.What is the maximal stretch of the spring?

**2. Equations**

F

_{s}=k times x

## The Attempt at a Solution

At the maximal stretch, the block is at equilibrium since it stops falling down. Gravity force is then equal to the spring force.

we have: F

_{s}=mg

kx = mg

so x = mg/k = 0.05*9.8 / 4 = 0.1225 meters

This answer is wrong.

Can anyone help me? My reasoning looks logic to me :(