- #1

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let m=mass

k=spring constant

x=displacement from equilibrium position

A=amplitude

T=period

By using conventional way, time taken to complete a quarter of cycle=T/4=(∏/2)√(m/k)

consider another way of doing, F=-kx

a=-(k/m)x

then we can consider the average acceleration of first quarter of motion a=(1/2)(k/m)A

since s=ut+1/2at^2

then, A=(1/2)*(1/2)(k/m)A*t^2

finally, we get t=2√(m/k)

why is the ans from both way diffrent...Both ways seem to be equivalent...