- #1

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what is the limitation of T = 2π [itex]\sqrt{\frac{m}{k}}[/itex]

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- Thread starter Hardik Batra
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- #1

- 130

- 5

what is the limitation of T = 2π [itex]\sqrt{\frac{m}{k}}[/itex]

Last edited:

- #2

tiny-tim

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Are you talking about a pendulum?

A pendulum is never

Since sinθ = θ - θ

that means the error will be a function of θ

to find out what function, just plough through the proof.

what is the limitation of T = 2π [itex]\sqrt{\frac{m}{k}}[/itex]

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