Simple Harmonic Motion

  • #1
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what is the limitation of T = 2π [itex]\sqrt{\frac{m}{k}}[/itex]
 
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Answers and Replies

  • #2
tiny-tim
Science Advisor
Homework Helper
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Hello Hardik! :smile:

Are you talking about a pendulum?

A pendulum is never exactly shm, but it is very nearly so if we assume θ = sinθ.

Since sinθ = θ - θ3/6 + …

that means the error will be a function of θ2/6 …

to find out what function, just plough through the proof. :wink:




what is the limitation of T = 2π [itex]\sqrt{\frac{m}{k}}[/itex]
 

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