# Simple Harmonic Motion

what is the limitation of T = 2π $\sqrt{\frac{m}{k}}$

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## Answers and Replies

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tiny-tim
Homework Helper
Hello Hardik!

Are you talking about a pendulum?

A pendulum is never exactly shm, but it is very nearly so if we assume θ = sinθ.

Since sinθ = θ - θ3/6 + …

that means the error will be a function of θ2/6 …

to find out what function, just plough through the proof.

what is the limitation of T = 2π $\sqrt{\frac{m}{k}}$