1. The problem statement, all variables and given/known data A particle of mass 4.00 kg is attached to a spring with a force constant of 100 N/m. It is oscillating on a frictionless, horizontal surface with an amplitude of 2.00 m. A 6.00-kg object is dropped vertically on top of the 4.00-kg object as it passes through its equilibrium point. The two objects stick together. What is the new amplitude of the vibrating system after the collision? 2. Relevant equations 3. The attempt at a solution Angular frequency before impact adding the block = (100/ 4)^1/2 = 5 s^-1 Angular frequency after impact adding the block = (100/ 10)^1/2 = 3.16 s^-1 Max acceleration before adding the block = Angular frequency^2 x amplitude = 25 x 2 = 50 ms^-2 Force of max acceleration = 50 x 4 = 200N After addition of the block, the max acceleration will be 200N/ (6 + 4) = 20 ms^-2 Max acceleration after adding the block = Angular frequency^2 x amplitude 20 = 3.16^2 x amplitude amplitude = 2 I know it is wrong but what is wrong, other than the fact my answer is exactly the same as the old amplitude.