Simple Harmonic Motion

shan

I just need someone to tell me if I've done the problem right since the answer is mysteriously missing

The question is about a rotating wheel causing a piston to execute SHM inside a cylinder (the piston being connected to the outside of the wheel). The wheel rotates with an angular speed of 12rads-1 and it has a radius of 30cm.

What will be the distance of the piston from an end position after 0.10s?

&omega; = &theta;/t

displacement from equilibrium point = amplitudexCos&theta; = 0.3xCos1.2 =0.1087m

so distance from end position = 0.3-0.1087 = 0.19m (2sf)

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lavalamp

Well I've read through it and it looks OK to me. Couldn't you just have asked your teacher though?

shan

School's out and I'm on my study leave...

lavalamp

Lucky you, I'm in school until almost Christmas. Then I have exams (with very little study leave) in January.

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