1. The problem statement, all variables and given/known data A very light, rigid rod with a length of 0.620m extends straight out from one end of a meter stick. The stick is suspended from a pivot at the far end of the rod and is set into oscillation. (a)Determine the period of oscillation. (b)By what percentage does this differ from a one meter long simple pendulum? 2. Relevant equations omega=sqrt((mgh)/i) omega=sqrt((g/l)) omega=(2Pi)/T 3. The attempt at a solution I got the correct period for part a, and it's 2.19s For the second part, I used omega=sqrt((g/l)), and omega is 3.13, and T is 2.007s. I used (2.19-2.007)/2.19 to find the percentage which is 0.0835. However, it's wrong... This seems like a simple question but I'm keep getting the second part wrong. Any suggestions???