Simple harmonic movement problem

I would really need help on these questions.

A mass is on a piston that oscillates vertically describing a S.H.M. T= 1s.

1-At which amplitude does the mass comes off the piston?
The answer is supposed to be 25 cm but I don't know how to find the position of the mass when it comes off the piston. I found w but I couldn't write the equation.

2- If the amplitude was 5 cm, what would be the maximum frequency so that the mass remains on the piston?
The answer is f=2,24 Hz


Homework Helper
The mass will leave the piston when the normal reaction between will be zero. This will happen when the acceleration of the piston is more then acceleration due to gravity.
Listen to mukundpa he put you on the right track but I want to add a couple of things.

1) Make sure your units match. If you use gravity in m/s^2 your distances must be in meters. (otherwise you can convert gravity to cm/s^2) same thing.

2) You need an eqn. for acceleration
b) if you do not have an eqn for accelration here is how to get one.
(I did this whole thing by comparing shm to circular motion)
Assume that the greatest acceleration is when the piston starts to go down (this drops out any sin from your eqn). Now use centripital acceleration and substitute for velocity (period and frequency will take its place)

3) No need to use w (omega), but it will help the 2Pi disappear.
The answer to b) seems to be 2.24Hz and not 2,24 Hz as you have written.
I got this from the equation Aw^2=g
Thanks for the help but now I have another question. This is probably stupid but I can't figure out why I get exactly the double for question a. I get 0.49m and the pulsation is equal to 2pi.


Homework Helper
Acceleration is maximum when the displacement is maximum(amplitude). For minimum amplitude for which the mass just leaves the piston the max. acceleration is g at the max. displacenrnt. Thus

w^2A = g
A = g/4Pi^2 = 9.8/4*9.87 = 0.248m which is close to 25 cm

some time g in m/s/s and pi^2 both are approximated to 10

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