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Attempt -

friend as per the question I am trying to get structure of SHM,

The displacement equation x = A sin(ωt + θ) represents SHM where ωt + θ is Phase of the particle.

the phase of the particle is 13∏/6. So I putting it on the equation and getting the result -

x = A/2. So I am getting the first answer.

While differentiating the displacement equation w.r.t. time I'll get velocity - time equation.

Which will be,

v = A.ω cos(ωt + θ)

Placing here the Phase of the particle I am getting the result,

v = A.ω.√3 / 2

So i am sticking here, is it representing the direction of the particle too ?

The correct answer of this problem is option (A) as per the question.

Please friends help me in solving this Problem.

Thank you all in advance.

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# Homework Help: Simple Harmonic Problem 3

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