Hi friends the problem is - https://fbcdn-sphotos-e-a.akamaihd.net/hphotos-ak-ash4/430884_2656507629229_1511525381_n.jpg Attempt - friend as per the question I am trying to get structure of SHM, The displacement equation x = A sin(ωt + θ) represents SHM where ωt + θ is Phase of the particle. the phase of the particle is 13∏/6. So I putting it on the equation and getting the result - x = A/2. So I am getting the first answer. While differentiating the displacement equation w.r.t. time I'll get velocity - time equation. Which will be, v = A.ω cos(ωt + θ) Placing here the Phase of the particle I am getting the result, v = A.ω.√3 / 2 So i am sticking here, is it representing the direction of the particle too ? The correct answer of this problem is option (A) as per the question. Please friends help me in solving this Problem. Thank you all in advance.