1. The problem statement, all variables and given/known data The 20cm long wrench swings on its hook with a period of 0.90s. When the wrench hangs from a spring of spring constant 360 N/m , it stretches the spring 3.0 cm. What is the wrench 's moment of inertia about the hook ? 2. Relevant equations torque =I alpha , Fsp =kx 3. The attempt at a solution I put R to be (14+.03) 1. The problem statement, all variables and given/known data 3. The attempt at a solution We need to find I and I = 1/2mg Consider Fsp = mg when the wrench is at the lowest point . -kx=mg and m=`kx/g but I dun know how to find the I as the pivot is not on the rotation and should I consider the wrench as a rod for the moment of inertia ?