I have two questions:(adsbygoogle = window.adsbygoogle || []).push({});

#1.) The velocity of a simple harmonic oscillator is given by

v=-7.22(26.0t) (mks units)

If the mass is 0.29kg, what is the spring's potential energy at the time t=40.33?

MY WORK:

First I found k by using ω^2=k/mass. This equaled 196.04.

I couldn't really figure out how I was supposed to derive aplitude (A) for that, So i figured since v=-Aω sin (ωt) that A =7.22/2.60.

Then i took my (probably not right) amplitude and put it into U=.5kA^2cos^2(ωt).

*This didn't work out, possibly because I can't figure out how to get the correct amplitude??

#2.) A 0.28 kg mass is attached to a vertical spring with a spring constant 9.1 N/m and let fall. What is the amplitude of the resulting motion?

MY WORK:

Since its a vertical spring, i used the equation: y0=mg/k. When I got the y0, i figured this to be twice my aplitude, so i divided it by 2.

*Wrong, again because I have issues with amplitude.

Please help me!!

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# Homework Help: Simple harmony

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