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Hello, I am new here and wish I had found this forum earlier in the semester. Here is the situation:

A block (mass m=0.75 kg) rests on a horizontal surface (frictionless), attached to a horizontal spring (k=235 N/m). At time t=0, the block is located at the equilibrium position (x=0), given a sove that compresses the spring. The block gains a speed of 2.5 m/s instantaneously.

(ii) What is the acceleration of the block at time, t=3.0 s?

The equation I have found that might be correct is:

a= -(kA/m)sin(2(pie)t/T), where t= 3.0s and T=.352 based on

T= 2(pie)sqrt(m/k)

Using this equation I arrived at -35.2 m/s2 (the negative is because of the direction of the acceleration at t= 3.0s). This answer makes sense in that the acceleration has slowed from a max acceleration of 43.8 m/s2.

Any suggestions, advice, criticisms?

Thanks for your help.

Todd

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# Simple Hrmonic Oscillation

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