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Simple inertia

  1. Feb 15, 2010 #1
    So I have a piston connected to a flywheel. If i push the piston with a force F, how does the equation of motion look? I'm not confident about putting inertias into the same equation as accelerations?

    F = ma

    F = I(theta'')

    The force is changing with time.

    EDIT:

    So i have just realised that T = Ia, a is angular acceleration.

    So if i find resultant force of piston acting along line of tangential velocity on the flywheel, then moultiply it by r of the flywheel,

    Fr = Ia, then rearrange for a and i have angular acceleration of flywheel?
     
    Last edited: Feb 15, 2010
  2. jcsd
  3. Feb 15, 2010 #2

    tiny-tim

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    Hi a.mlw.walker! :smile:

    (have a tau: τ and a theta: θ and an omega: ω and an alpha: α :wink:)
    That's right …

    the standard linear equations apply, with τ I θ ω and α instead of F m s v and a. :wink:
     
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