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## Homework Statement

An applied force varies with position according to F = k

_{1}x

^{n}- k

_{2}, where n = 3, k

_{1}= 8.3 N/m

^{3}, and k

_{2}= 87 N. How much work is done by this force on an object that moves from x

_{i}= 6.47 m to x

_{f}= 14.9 m? Answer in units of kJ.

## Homework Equations

W = k

_{1}x

^{4}/4 ]from the integral of x

_{1}to x2

- k

_{2}x]from x

_{1}to x

_{2}

## The Attempt at a Solution

I plugged in everything, and I got 96.778 at first, then I thought I should use x3

^{3}/3, then I got 6.543478 kJ.

I got both them wrong, did I do the calculation wrong? Please help, thanks. :D

SOLVED

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