1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Simple integration problem

  1. May 16, 2009 #1
    Hi all, im having a problem with an integration.


    Solve the integration 3/(1+4x)^0.5 between x=0 and x=2. Basically find the area under a curve of the equation between x=0 and x=2.

    I know the answer is 3 but cant get to it. I tried rewriting it as 3(1+4x)^-0.5 and solving bu got stupid answers like 15. and 21 to lots of dp. I cant find the mark scheme to the past paper i am doing anywhere on the internet so cant find a solution. Help would be much appreciared, thanks
     
  2. jcsd
  3. May 16, 2009 #2
    If you let u=1+4x, then the integral becomes 3/4*u^(-1/2)du for u from 1 to 9.
     
  4. May 16, 2009 #3
    3/(1+4x)^0.5 = 3 * (1+4x)^(-0,5)

    Now you can use the common powers law with the exponent (-0,5).
    Adding 1 to this gives (0,5).
     
    Last edited: May 16, 2009
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Simple integration problem
  1. Simple problem (Replies: 4)

  2. Integrating problem ? (Replies: 2)

  3. Integration problem (Replies: 9)

  4. Simple integration (Replies: 5)

  5. Simple (?) problem (Replies: 2)

Loading...