Hey everyone. One of the steps at the end of this problem is confusing to me. I'll point it out.(adsbygoogle = window.adsbygoogle || []).push({});

[tex]

\int \frac{1}{1+ \sqrt{2x}} dx

[/tex]

Setting u equal to [tex] {1+ \sqrt{2x}} [/tex] and du equal to [tex] \frac {1}{\sqrt(2x)} [/tex] and taking the derivative, I get

[tex]

\int \frac {sqrt(2x)}{u} du

[/tex]

The answer to the problem is apparently as follows -

[tex]

\equiv \sqrt{2x} - ln|1+ \sqrt{2x}| + c

[/tex]

As far as I'm aware there is no step in between those last two. I'm not sure how it works and I'm 90% sure that I'm just missing something extremely obvious. I'd appreciate any help. Thank you!

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# Simple Integration (U-sub/LN)

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