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Simple Integration

  1. Sep 16, 2008 #1
    Hi, I've got to solve for: [tex]\int\stackrel{3}{1}[/tex](4x2+2)dx

    This is what I've done:

    = [ (4/3)x3 + 2x ][tex]\stackrel{3}{1}[/tex]
    = [ (4/3)(3)3 + 2(3) ] - [ (4/3)(1)3 + 2(1) ]
    then I solved...

    = 44/3

    Is that correct at all?
     
  2. jcsd
  3. Sep 16, 2008 #2
    looks good to me! If you have done the arithmetic correctly of course!
     
  4. Sep 16, 2008 #3
    Awesome! My morale just sky rocketed...

    By the way, sorry for the bad latex graphic thing... I'm having a hard time figuring that out.
     
  5. Sep 16, 2008 #4
    [tex] \int_{1}^3 (4x^2+2)dx[/tex]
     
  6. Sep 16, 2008 #5
    Cool thanks. Could you check out this thread again?
     
  7. Sep 17, 2008 #6
    Your math looks good, but you made an error in your calculation. I'm getting 116/3.
     
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