Hi, I've got to solve for: [tex]\int\stackrel{3}{1}[/tex](4x(adsbygoogle = window.adsbygoogle || []).push({}); ^{2}+2)dx

This is what I've done:

= [ (4/3)x^{3}+ 2x ][tex]\stackrel{3}{1}[/tex]

= [ (4/3)(3)^{3}+ 2(3) ] - [ (4/3)(1)^{3}+ 2(1) ]

then I solved...

= 44/3

Is that correct at all?

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# Simple Integration

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