Simple Intro Physics question

  • Thread starter Grandmas
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  • #1
Grandmas
8
0
To many this would be a simple plug it into equation problem. But for some reason this just isn't clicking for me. Here's the problem:

An open elevator is ascending with a constant speed V of 32ft/sec. A ball is thrown straight up by a boy in the elevator when it is a height h of 100 feet above the ground. The initial speed of the ball with repect to the elevator is Vo= 64ft/sec. (A) What is the maximum height attained by the ball? (B) How long does it take for the ball to return to the elevator?

I don't know where to start or what to plug in, please help me out, much appreciated and thanks. :frown:
~Grand
 

Answers and Replies

  • #2
snooper007
33
1
(A) [tex]\frac{64 \times 64}{2G}[/tex]
G is the Newton acceleration constant, in international units, it is [tex]9.8 meter/sec^2[/tex].
I don't know how to convert to your unit, ft! you must convert G to ft.
(B) [tex]\frac{64}{G}[/tex]
 
  • #3
Mk
2,037
4
snooper007 said:
(A) [tex]\frac{64 \times 64}{2G}[/tex]
G is the Newton acceleration constant, in international units, it is [tex]9.8 meter/sec^2[/tex].
I don't know how to convert to your unit, ft! you must convert G to ft.
(B) [tex]\frac{64}{G}[/tex]
In physics you should use SI units anyway.
 

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