# Simple Kinematics problem

## Homework Statement

A small steel ball, dropped from rest, takes 0.5s to fall through a vertical distance of 1.25m.
Determine the actual speed of the ball when it has fallen through a vertical distance of 1.25m, assuming that acceleration is constant.

v=s/t

## The Attempt at a Solution

Long ago I was helped by a friend to get the result
( 1.25m x 2 ) / 0.5s = 5ms-1

but I've forgotten how did he come to that conclusion, and the reason behind (1.25mx2), help is much appreciated .

Cyosis
Homework Helper
The formula $s=vt$ is only valid for constant speed. Does an object fall with constant speed?

Your friend used the following, correct equations:

1) $s=\frac{1}{2}at^2+v_0t+x_0$
2) $v=at+v_0$

These are valid for constant acceleration. You will need to combine both of them to get the answer.

s = t*(u+v)/2