A small steel ball, dropped from rest, takes 0.5s to fall through a vertical distance of 1.25m.
Determine the actual speed of the ball when it has fallen through a vertical distance of 1.25m, assuming that acceleration is constant.
The Attempt at a Solution
Long ago I was helped by a friend to get the result
( 1.25m x 2 ) / 0.5s = 5ms-1
but I've forgotten how did he come to that conclusion, and the reason behind (1.25mx2), help is much appreciated .