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Simple Kinematics Question

  1. Sep 22, 2006 #1
    A stone (taken as a point mass) is thrown from a cliff of height H = 80m perpendicular to the ground. It falls L = 60m away from the cliff. What is the initial velocity V with which the stone is thrown?

    Obviously we have to deduce the formula for velocity using kinematic equations w/ respect to H and L. Help will be very appreciated. Thank you.
     
  2. jcsd
  3. Sep 22, 2006 #2

    radou

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    Think of the equations of motion for both the x and y direction. In which direction is the velocity constant? IN which direction does gravity act?
    Btw, the angle of the throw is not given?
     
  4. Sep 22, 2006 #3
    g acts in y direction. velocity is constand is x direction. angle of throw, as mentioned, is perpendicular to the ground, and sincs cos90 = 1 it can be neglected.

    i need help solving it.
     
  5. Sep 22, 2006 #4

    nrqed

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    Just list what you know
    [itex] a_x = 0, a_y = -9.80 m/s^2, x_i=y_i=0, x_f=60 m, y_f =-80 m, v_{yi}=0 [/itex] and what you are looking for is [itex] v_x [/itex].

    Just write the equations along x and along y that you will need. Notice that you will have to find the time as well. So the idea is to find the time using the y equation and then use that in the equation along x to find the velocity.
     
  6. Sep 22, 2006 #5
    thanks, all done
     
  7. Sep 22, 2006 #6
    In the same problem, what is the time taken by the body to attain a velocity twice its initial velocity?

    What is the displacement of the body at that time?
     
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