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Simple kinmatics

  1. Feb 16, 2005 #1


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    A person stands on the roof of a building, 40 m high. He throws a rock directly up at 10 m/s. How long until it hits the ground?

    I know how to do this in 2 steps: compute height that the rock rises to (~5 meters), then compute time for an object to free fall from 0 m/s to the ground ~45 meters below.

    But isn't there a way to do it in one step?
  2. jcsd
  3. Feb 16, 2005 #2


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    You certainly should be able to get the formula for height as a function of time: you probably use it or some version of it to get the height the rock rises to.
    It is h= -4.9t2+ 10t+ 40.

    Now set h= 0 and solve for t (you will get two solutions- only one is positive).
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