- #1

- 224

- 0

i.e.:

x - 1 = 4t

y - 5 = 3t

z - 2 = 7t,

the vector <4, 3, 7> (coefficients of t) is a vector parallel to that line.

My notes clearely say that the vector <4, 3, 7> is a normal vector to the parametrized line.

Which one is right?

Thanks.

- Thread starter Physics_wiz
- Start date

- #1

- 224

- 0

i.e.:

x - 1 = 4t

y - 5 = 3t

z - 2 = 7t,

the vector <4, 3, 7> (coefficients of t) is a vector parallel to that line.

My notes clearely say that the vector <4, 3, 7> is a normal vector to the parametrized line.

Which one is right?

Thanks.

- #2

- 76

- 0

It should be parallel.

- harsh

- harsh

- #3

- 224

- 0

Ok thanks. That's what I thought...I should drink some caffiene before I go to class and take notes.

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