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Simple Loop Problem

  1. Oct 14, 2008 #1
    1. The problem statement, all variables and given/known data
    A bead slides without friction around a loop-the-loop as shown in the figure below. The bead is released from a height h = 3.75R.

    (a) What is the bead's speed (V) at point A? Answer in terms of R and g, the acceleration of gravity.

    I don't have the picture it's in the book so I'll describe it. It's a downward slope that go's into a loop. 'A' is at the the top of the loop and R is the loop's radius.


    2. Relevant equations

    a=v^2/r

    3. The attempt at a solution

    Since it's perfectly parallel with the y axis, and therefor i assume a is 9.81, I get (gr)^1/2, but my webassignment program says that's wrong.
     
    Last edited: Oct 14, 2008
  2. jcsd
  3. Oct 15, 2008 #2

    tiny-tim

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    Hi Guruu! :smile:

    What does a=v^2/r have to do with part (a)? :confused:

    Hint: use conservation of energy. :smile:
     
  4. Oct 15, 2008 #3
    yup conservation of energy is the way to go
     
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