Simple Machines

  • Thread starter fiosuer
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  • #1
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What equation is used to solve a problem similar to the one below?

What force must be applied to the end of a 2.0 meter long crowbar in order to lift
a 500 newton rock if the fulcrum of the bar is .5 meters from the rock?

Thanks.
 

Answers and Replies

  • #2
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Would it be something like f1d1=f2d2?
Therefore, (500 N)(2.0 meters) = (x N)(0.5 meters). And the answer is 200 N?
 
  • #3
403
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Would it be something like f1d1=f2d2?
Therefore, (500 N)(2.0 meters) = (x N)(0.5 meters). And the answer is 200 N?
THe equation is correct.. What is means is that f1 is applied at distance d1 from the fulcrum and F2 is applied a distance d2 from the fulcrum.

I recommend that you sketch the situation to help select the correct values to substitute.
 
  • #4
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THe equation is correct.. What is means is that f1 is applied at distance d1 from the fulcrum and F2 is applied a distance d2 from the fulcrum.

I recommend that you sketch the situation to help select the correct values to substitute.
Is it 2.0 - 0.5 = 1.5?
(500 N)(1.5 meters) = (x N)(0.5 meters). And the answer is 1500N?
 
  • #5
403
36
Is it 2.0 - 0.5 = 1.5?
(500 N)(1.5 meters) = (x N)(0.5 meters). And the answer is 1500N?
That would be true of the 500 N rock were 1.5 m from the fulcrum. THe questions says it is 0.5 m from the fulcrum.
 

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