# Simple Machines

What equation is used to solve a problem similar to the one below?

What force must be applied to the end of a 2.0 meter long crowbar in order to lift
a 500 newton rock if the fulcrum of the bar is .5 meters from the rock?

Thanks.

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Would it be something like f1d1=f2d2?
Therefore, (500 N)(2.0 meters) = (x N)(0.5 meters). And the answer is 200 N?

Would it be something like f1d1=f2d2?
Therefore, (500 N)(2.0 meters) = (x N)(0.5 meters). And the answer is 200 N?
THe equation is correct.. What is means is that f1 is applied at distance d1 from the fulcrum and F2 is applied a distance d2 from the fulcrum.

I recommend that you sketch the situation to help select the correct values to substitute.

THe equation is correct.. What is means is that f1 is applied at distance d1 from the fulcrum and F2 is applied a distance d2 from the fulcrum.

I recommend that you sketch the situation to help select the correct values to substitute.
Is it 2.0 - 0.5 = 1.5?
(500 N)(1.5 meters) = (x N)(0.5 meters). And the answer is 1500N?

Is it 2.0 - 0.5 = 1.5?
(500 N)(1.5 meters) = (x N)(0.5 meters). And the answer is 1500N?
That would be true of the 500 N rock were 1.5 m from the fulcrum. THe questions says it is 0.5 m from the fulcrum.