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- Thread starter PhunWithPhysics
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Fermat

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Do a balance of momentum at the start to get a ratio of the two separation speeds.

Then apply the eqns of motion to the movement of each skater and solve for the unknown ratio.

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There is no momentum at the start so initial momentum is 0. So how do I solve for the masses if there are no mases?

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0 = M1v-M2v (because they are going in opposite directions..so..

M1v = M2v ?

M1v = M2v ?

Last edited:

- #6

dekoi

Of course there is initial momentum if the two skaters are both moving.PhunWithPhysics said:There is no momentum at the start so initial momentum is 0. So how do I solve for the masses if there are no mases?

p = mv

And we know that both skaters do have velocity and mass.

There are no numerical masses so you are solving for the variables M1 and M2, using equations. It will most likely turn out that the ratio will be expressed without varibles, and as a number.

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They arent moving at the beginning.dekoi said:Of course there is initial momentum if the two skaters are both moving.

p = mv

And we know that both skaters do have velocity and mass.

There are no numerical masses so you are solving for the variables M1 and M2.

- #8

dekoi

Sorry, I misread the question.

- #9

Fermat

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They are moving at different velocities, so it's more a case of,alias25 said:0 = M1v-M2v (because they are going in opposite directions..so..

M1v = M2v ?

M1.V1 = M2.V2

M1/M2 = V2/V1

Let M1/M2 = λ, say

then,

V2 = λ.V1

========

Now do the eqns of motion bit, where both masses have the same deceleration, you know the start and end velocities of each mass, and M1 travels twice the distance that M2 does.

Solve for λ.

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