Is this equation equal to: (e^(hf/kT)) - 1 or e^( (hf/kT) - 1 ) http://s29.postimg.org/le6iqy3rb/exp.png
First off, what you wrote is NOT an equation. An equation always has an = symbol in it. The image in the link is [exp(hf/kT) - 1]. What you have written is ambiguous, as what you probably meant is this: $$e^{\frac{hf}{kT} - 1}$$ What you actually wrote, though, is this: $$e^{\frac{hf}{k}T - 1}$$ The brackets - [] - around the entire expression are unnecessary.
Why did you put the -1 in the exponential? The parenthesis limit the argument of exp to hf/kT. My guess is that Mechatron did not write that himself, but saw it in a book. It's most probably related to the Planck distribution (blackbody radiation). As economicsnerd said, the correct reading is $$ e^{\beta h f} - 1 \mbox{ where } \beta = \frac{1}{kT} $$ The additional bracket [] might be there because it is part of a greater equation.
Im sorry to be off topic but I'm using a i device and i can't see (what i think to be) mathematical symbols that are in this thread... They appear as dollar signs and other randoms, i was wondering if maybe I'm short of additional download or setting adjustments. All help is highly appreciated
The posted image, which doesn't have the -1 term, doesn't match the expressions in the first post. In the first post Mechatron asks about these expressions: (e^(hf/kT)) - 1 and e^( (hf/kT) - 1 ) In any case, this is moot, as Mechatron has been banned from PF.