((-6)^ 1/2 ) ( (-7)^1/2) = (42)^1/2frozen7 said:((-6)^ 1/2 ) ( (-7)^1/2) = (42)^1/2
((-6)^ 1/2 ) ( (-7)^1/2) = (6^ 1/2 ) ( 7^1/2) ( i ^2)
= -(42)^1/2
Can anyone tell me where I did wrong?
The square root of a negative number is an imaginary number, represented by the letter "i". In this case, the square root of -6 is 2i and the square root of -7 is i√7.
To solve for square roots with exponents, you can use the power rule for exponents, which states that (a^m)^n = a^(m*n). In this case, we can rewrite the equation as (-6)^(1/2 * 1) * (-7)^(1/2 * 1) = (42)^(1/2).
The product of two square roots is equal to the square root of the product of the two numbers. In this case, the product of √(-6) and √(-7) is equal to √(-6 * -7) = √42.
Yes, the square root of a negative number can be simplified by converting it to an imaginary number. In this case, we can simplify √(-6) as 2i and √(-7) as i√7.
To solve for the square root of a number with an exponent, you can use the power rule for exponents, which states that (a^m)^n = a^(m*n). In this case, we can rewrite the equation as (√(-6))^2 * (√(-7))^2 = (√42)^2. Then, we can simplify and solve for the square root of 42, which is √42 = 6.48.