Simple momentum question

  • Thread starter oridniv
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  • #1
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So, we were given a scenario and were asked to not calculate the momentum components in the x- directions. We were asked to use the simple formula of momentum(p) p=mv. Velocity was the root of the distance between the collisions and the mass was 1 unit. No specific units are to be used in these calculations. The question asks us to calculate momentum in the y-direction after being given specific angles. What's the difference between the distance and the y- component again?
 

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  • #2
cristo
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It'll be easier for someone to answer if you state the exact question you are trying to solve, along with the work you have done on it (i.e. what you have calculated)
 
  • #3
9
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1st scenario:
d=9.4cm
v= square root d= 3.1
I dunno how to calculate the y-components of momentum considering on an x-y plane, d is 34 degrees north of west. What I calculated was 9.4sin34 to get the y components but I can't shake the feeling that I might be wrong

2nd scenario, same as first but different numbers
d=14.7
v=3.83
d is 94 degrees east of north
y-component=14sin93
 
  • #4
340
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Could you state the whole question as given. It is quite confusing to me now.
 
  • #5
9
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don't worry, my prof explained and it now makes sense, thanx tho
 

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