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## Homework Statement

A simple pendulum of mass 19 kg is displaced an angle of 13 degrees from vertical and released. It now has a period of 2 sec.

a) Its mass is doubled. What is its period now?

T2m = 2 sec

b) Its length is doubled. What is its period now?

T2L = 2.828 s

c) What if the original pendulum is only displaced a distance of 6.5 before being released. What is its period now?

TΘ/2 = 2 sec

d) The original pendulum is taken to a planet where g = 15 m/s2. What is its period on that planet?

T = 1.6174 s

e) Let's go back to the original pendulum of mass 19 kg with a period of 2 sec, displaced an angle of 13 degrees from the vertical. What would its acceleration be in the vertical (y) direction as it reachs the lowest point on its swing?

ay = _______ m/sec2

## Homework Equations

T=2[tex]\Pi[/tex][tex]\sqrt{L/g}[/tex]

## The Attempt at a Solution

I solved all of the questions except for part e.

I thought it might be zero, but that didn't work.

I'm not sure what to do since I don't know the length or anything.

Thanks for your help in advance!