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Simple pendulum question

  1. Nov 9, 2006 #1
    still reviewing my test and im having trouble.

    A pendulum consists of a bob of mass 0.14kg at the end of a light string of lenght 0.66 meters, whose other end is fixed. the number of oscillations executed by the pendulum each minute is....?

    so far this is what ive got

    L= (gT^2) / (4pi^2) solve for T, i get 1.629 seconds..

    where do i go from here?
     
  2. jcsd
  3. Nov 9, 2006 #2
    i think i got it.. it takes 1.629 seconds for one oscillation.. we're solving for number of oscillations per min. so divide 60 by 1.629.. would be 36.8 oscillations per minute?

    correct? anyone?
     
  4. Nov 9, 2006 #3

    OlderDan

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    Looks like you got it. A useful bit of trivia.. when L = 1 meter the period is very close to 2 seconds.
     
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