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Simple Pendulum Question

  1. Feb 14, 2005 #1
    Simple pendulum has T = 2pi rt (l/g) when oscillating at a natural frequency of vibration. (Small angles of course)

    Calc. new T of pendulum when oscillating in a car with acceleration a.

    Any tips? Thanks. :)
  2. jcsd
  3. Feb 14, 2005 #2
    Can anyone do this question? Cheers.
  4. Feb 14, 2005 #3
    [tex]T=2\pi \sqrt{\frac{l}{\sqrt(a^2+g^2)}}[/tex]
  5. Feb 14, 2005 #4
    Cheers Clive - Would you mind explaining (or any1 else) how you arrived at that answer? thanks.
  6. Feb 14, 2005 #5

    Doc Al

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    Staff: Mentor

  7. Feb 14, 2005 #6
    Thanks very much, it certainly was! I understand that totally! You found the effective g acting on the pendulum by summing the individual accelerations acting on the pendulum, using vectors. Great. :)
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