- #1

- 971

- 40

## Homework Statement

## Homework Equations

## The Attempt at a Solution

Actual time taken by the object to fall by a distance h on earth = ##t = \sqrt{\frac{2h}{g}}##

Measured time by pendulum clock on earth = t

Actual time taken by the object to fall by a distance h on moon = ##t '= (\sqrt{6})\sqrt{\frac{2h}{g}}##

If actual time is t then time measured by pendulum clock on moon = ##\frac{t}{\sqrt{6}}##

Taking the above two factors into account , Time taken by the object to fall by a distance h on moon as measured by pendulum clock = t . Thus option a) is correct .

But the answer given is both a) and b) .

Now I wonder how can the measured speeds be same as speed ##v_{moon}## = (acceleration due to gravity on moon ) (time as measured by pendulum clock on moon ) .

Since ##g_{moon} = \frac{g}{6}## , speed after falling through 'h' as measured on moon ##v_{moon}## = ##\frac{v_{earth}}{6}## .

So, my doubt is , how is option b) correct and mistake in my reasoning .

I might be missing something .

Thanks