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Simple percentage problem

  1. Aug 10, 2009 #1
    1. The problem statement, all variables and given/known data

    In the following exoergic nuclear reaction,

    12D + 13T &rarr 01n + 24He

    what percentage of the initial mass is converted into energy?



    2. Relevant equations

    (mA +ma)- (mB-mB) =delta m

    delta m * u(MeV) = E



    3. The attempt at a solution

    I'm not sure how to do sub and super scripts but 12D would be deuterium. Anyway I calculted the masses and got (mA+ma)5.03u for the first and (mB+Mb)5.011 for the second. To get the % of the mass converted to energy I divided mb+mB/mA+mA and got 99.6%. A I doing it correctly...(even if I calculated the masses incorrectly)
     
  2. jcsd
  3. Aug 10, 2009 #2

    tms

    User Avatar

    The number you got, 99.6% (assuming the masses and the arithmetic are right), is the percentage of the original mass *not* converted to energy.
     
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