Simple physics 11 problem ?

  • Thread starter roxxyroxx
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  • #1
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Homework Statement



A 15.0 g object initially moving to the right at 30.0 cm/s collides with a stationary 45.0 g object. After the collision the 45.0 g object is moving to the right at 15 cm/s.
what impulse does the 45.0 g object apply to the 15.0g object during collision?

Homework Equations



F[tex]\Delta[/tex]t = m[tex]\Delta[/tex]v

The Attempt at a Solution



I tried:
F[tex]\Delta[/tex]t = m[tex]\Delta[/tex]v
= (15.0g)(15.0cm/s)
= 225 N x s
but the answer is 6.75 x 10^-3 N x s
help ?
 

Answers and Replies

  • #2
Doc Al
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I tried:
F[tex]\Delta[/tex]t = m[tex]\Delta[/tex]v
= (15.0g)(15.0cm/s)
= 225 N x s
but the answer is 6.75 x 10^-3 N x s
How did you determine the change in velocity of the 15.0g object?

(Also: Use standard units. Convert g to kg; cm to m.)
 

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