The position of an object is given by x= bt^3, where x is in meters, t is in seconds, and where the constant b is 1.5 m/s^3. Determine (a) the instantaneous velocity and (b) the instantaneous acceleration at the end of 2.5s. Find (c) the average velocity and (d) the average acceleration during the first 2.5s.(adsbygoogle = window.adsbygoogle || []).push({});

taking the derivative of x will give me the velocity and taking the derivative of velocity will get me the acceleration, so...

x= bt^3

v= 3bt^2

a= 6bt

here are my answers (please check them):

a) bt^3/2.5

b) 3bt^2/2.5

c) bt^3/2.5

d) 3bt^2/2.5

can someone check these answers and tell me if i'm doing them correctly?

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# Homework Help: Simple physics question

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