 #1
 74
 0
1. Homework Statement
Determine I_0 in the network.
2. Homework Equations
P = VI
Passive Sign Convention Rule
3. The Attempt at a Solution
Here's what I did. I calculated the power absorbed/supplied by the bottom left network.
Element 3: P = VI = (6V)(I_0 A) = 6I_0 W
Element 5: P = VI = (6V)(4A) = 24 W
Element 6: P = VI = (8V)(6A) = 48 W
VDependent Source: P = VI = (4 * 2 A)(6A) = 48 W (I did this because of the passive sign convention.
6I_0 + 24 + 48  48 = 0
I_0 = (24) / 6
I_0 = 4 A
It says something is wrong, but I'm not sure why. I'm 99% sure I followed the rules for PSC. I've attached an image of the circuit. I've done it only using this loop, but also, if you check down below, I've done it for every element (I get differing answers).
Thanks
(Circuit picture taken from WileyPLUS homework, please do not redistribute/copy).

If I had to calculate each element, in the WHOLE entire network, would this work be correct:
E1: 64W
E2: 60W
E3: I_0 * 6 W
Independent 24V Source: 192W
E4: 32W
E5: 24W
E6: 48W
Dependent 4I_x V Source: 48W
so... (Im going to leave out the W unit in the equation for now, so it doesn't confuse anyone)
64 + 60 + 6I_0 + (192) + 32 + 24 + 48  48 = 0
6I_0 + (12) = 0
6I_0 = 12
I_0 = 2A
Determine I_0 in the network.
2. Homework Equations
P = VI
Passive Sign Convention Rule
3. The Attempt at a Solution
Here's what I did. I calculated the power absorbed/supplied by the bottom left network.
Element 3: P = VI = (6V)(I_0 A) = 6I_0 W
Element 5: P = VI = (6V)(4A) = 24 W
Element 6: P = VI = (8V)(6A) = 48 W
VDependent Source: P = VI = (4 * 2 A)(6A) = 48 W (I did this because of the passive sign convention.
6I_0 + 24 + 48  48 = 0
I_0 = (24) / 6
I_0 = 4 A
It says something is wrong, but I'm not sure why. I'm 99% sure I followed the rules for PSC. I've attached an image of the circuit. I've done it only using this loop, but also, if you check down below, I've done it for every element (I get differing answers).
Thanks
(Circuit picture taken from WileyPLUS homework, please do not redistribute/copy).

If I had to calculate each element, in the WHOLE entire network, would this work be correct:
E1: 64W
E2: 60W
E3: I_0 * 6 W
Independent 24V Source: 192W
E4: 32W
E5: 24W
E6: 48W
Dependent 4I_x V Source: 48W
so... (Im going to leave out the W unit in the equation for now, so it doesn't confuse anyone)
64 + 60 + 6I_0 + (192) + 32 + 24 + 48  48 = 0
6I_0 + (12) = 0
6I_0 = 12
I_0 = 2A
Attachments

11.9 KB Views: 293
Last edited: