1. The problem statement, all variables and given/known data 1. A 0.3 kg apple falls from rest through a height of 40 cm onto a ﬂat surface. Upon impact, the apple comes to rest in 0.1 s, and 4 cm2 of the apple comes into contact with the surface during the impact. What is the average pressure exerted on the apple during the impact? Ignore air resistance. (A) 67,000 Pa (B) 21,000 Pa (C) 6,700 Pa (D) 210 Pa (E) 67 Pa (the answer is b) 2. Relevant equations p = mv f = Δp/Δt v = √(2gh) pressure = force / surface area 3. The attempt at a solution The velocity the apple is traveling at when it hits the ground is v = √(2gh) = √(2* 10 * 0.4) = 2.83 m/s The average force on the apple is Δp/Δt = (0.3 * 2.83) / (0.1) = 8.48 N So the average pressure on the apple should be force/surface area = 8.48/(0.042) = 5300 Pa But that is not an answer. What did I do wrong?