# Homework Help: Simple Probability

1. Jan 14, 2010

### exitwound

I'm new to Statistics. Never had it in High School and now I'm in Elementary Statistics in college. I'm less than a week into class and I'm lost. Perhaps you could help.

1. The problem statement, all variables and given/known data
I have the answer to this as it's a practice question from the book. I don't know how to get it.
Consider the type of clothes dryer (gas or electric) purchased by each of five different customers at a certain store.

a.) If the probability that at most one of these purchases an electric dryer is .428, what is the probability that at least two purchase an electric dryer?

b.) If P(all five purchase gas) = .116 and P(all five purchase electric) = .005, what is the probability that at least one of each type is purchased?

2. Relevant equations

P(A') = 1 - P(A)
Others, maybe?

3. The attempt at a solution

a.) If P(at most one buys electric), then P(at least 2 buys electric) is 1-P(at most one buys electric). So, P(at least 2 buys electric) = .572, correct?

b.)
P(All 5 Gas) = .116
P(All 5 Elec) = .005

That's as far as I get, writing down the numbers. I have no idea where to go. In fact, I'm having an awful trouble with this material altogether. I just can't visualize any of it, or put what I'm trying to do into words easily.

Last edited: Jan 14, 2010
2. Jan 14, 2010

### Dick

It's the same reasoning as the first one. Think about it. If it's NOT true that 5 gas or 5 electric were purchased, then at least one of each was purchased. So P(at least one of each)+P(all 5 gas)+P(all 5 electric)=1.

3. Jan 14, 2010

### exitwound

I don't understand your reasoning for assembling the equation that way. As I said, I'm having a really hard time equating the basic probability equations to the ideas in this chapter. I understand that the sample space = 1, but not the left side.

4. Jan 14, 2010

### Dick

It's logic. One and only one of the alternatives on the left can occur. So they cover the whole sample space. So their sum is 1. Take any sale pattern that can occur, think about which pattern it fits.