1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Simple probability

  1. Jun 22, 2014 #1

    benorin

    User Avatar
    Homework Helper

    1. The problem statement, all variables and given/known data
    Suppose u have a deck composed of 4 aces and 2 kings. Find P(exactly 3 aces when u draw 3 cards), P(exactly 1 king and 2 aces when u draw 3 cards), and P(exactly 2 kings and 1 ace when u draw 3 cards).


    2. Relevant equations



    3. The attempt at a solution
    P(exactly 3 aces when u draw 3 cards)=4/6*3/5*2/4=1/5
     
  2. jcsd
  3. Jun 22, 2014 #2

    adjacent

    User Avatar
    Gold Member

    You do the same thing for (exactly 1 king and 2 aces when u draw 3 cards) and (exactly 2 kings and 1 ace when u draw 3 cards). However, you will have to consider the order of taking kings and aces. You will need Or rule too.
    Drawing a tree diagram is very helpful
     
    Last edited: Jun 22, 2014
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Simple probability
  1. Simple Probability (Replies: 3)

  2. Simple probability? (Replies: 1)

Loading...