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Simple problem on optical isomerism

  1. Sep 13, 2013 #1
    1. The problem statement, all variables and given/known data
    Is this compound optically active or inactive??

    2. Relevant equations Untitled.jpg

    3. The attempt at a solution
    This compound doesnt have the plane of symmetry.So according to me it should be optically inactive.is it right??
  2. jcsd
  3. Sep 13, 2013 #2


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    Staff: Mentor

    It doesn't?

    What you wrote suggests lack of plane of symmetry makes the compound optically inactive. Are you sure about it?
  4. Sep 13, 2013 #3
    sorry i mean it should be optically active.
  5. Sep 13, 2013 #4


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    Staff: Mentor

    So, where is the chiral atom?

    I guess you should start finding out how to deal with rings...

    Also remember that while the molecule is drawn flat, in fact it is not flat at all - which is especially important for carbons substituted with methyls and Cl.
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