1. Sep 13, 2013 #1

   nil1996

   

   1. The problem statement, all variables and given/known data
   Is this compound optically active or inactive??
   
   
   
   2. Relevant equations
   
   
   
   3. The attempt at a solution
   This compound doesnt have the plane of symmetry.So according to me it should be optically inactive.is it right??

    

   nil1996, Sep 13, 2013
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3. Sep 13, 2013 #2

   Borek

   

   Staff: Mentor

   It doesn't?
   
   

   What you wrote suggests lack of plane of symmetry makes the compound optically inactive. Are you sure about it?

    

   Borek, Sep 13, 2013
4. Sep 13, 2013 #3

   nil1996

   

   sorry i mean it should be optically active.

    

   nil1996, Sep 13, 2013
5. Sep 13, 2013 #4

   Borek

   

   Staff: Mentor

   So, where is the chiral atom?
   
   I guess you should start finding out how to deal with rings...
   
   Also remember that while the molecule is drawn flat, in fact it is not flat at all - which is especially important for carbons substituted with methyls and Cl.

    

   Borek, Sep 13, 2013

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