Simple problem on optical isomerism

  • Thread starter nil1996
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  • #1
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Homework Statement


Is this compound optically active or inactive??



Homework Equations

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The Attempt at a Solution


This compound doesnt have the plane of symmetry.So according to me it should be optically inactive.is it right??
 

Answers and Replies

  • #2
Borek
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This compound doesnt have the plane of symmetry.
It doesn't?

So according to me it should be optically inactive.is it right??
What you wrote suggests lack of plane of symmetry makes the compound optically inactive. Are you sure about it?
 
  • #3
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sorry i mean it should be optically active.
 
  • #4
Borek
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28,629
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So, where is the chiral atom?

I guess you should start finding out how to deal with rings...

Also remember that while the molecule is drawn flat, in fact it is not flat at all - which is especially important for carbons substituted with methyls and Cl.
 

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