1. The problem statement, all variables and given/known data "A rock is dropped off a cliff into the water below. The sound of the splash is heard 3.0 s later. If the speed of sound is 332 m/s, calculate the height of the cliff above the water. (Note: the total time it takes for the rock to fall and the sound to travel upwards is 3.0 s)" Therefore, v1 = 0 g = 9.8 m/s2 Δt = 3.0 s vsound = 332 m/s 2. Relevant equations FOR SOUND Δd = vsound * Δt2, where Δt2 is the time it takes from the sound to reach the top of the cliff from the bottom. FOR ROCK Δd = v1 * Δt + 0.5 * g * (Δt)2 *the following equations may be useful but i doubt it* v2 = v1 + g * Δt (v2)2 = (v1)2 + 2 * g * Δd *assume no air resistance 3. The attempt at a solution Δd = ? No clue. I figured that the answer should be 41 m, I believe, by trial and error but I would like to know how this can be solved in a normal way.